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Chemistry 20 Online
OpenStudy (anonymous):

how many kilogram of wet NaOH containing 12% water are required to prepare 60 litre of 0.50 N solution?

OpenStudy (anonymous):

@DLS @skullpatrol @satellite73

OpenStudy (anonymous):

hlp me out

OpenStudy (dls):

calculate no. of moles

OpenStudy (dls):

60 litre of 0.50 N solution?

OpenStudy (anonymous):

yes

OpenStudy (dls):

i mean calculate no.of moles in 60 litre of 0.50 N solution

OpenStudy (anonymous):

answer is nt coming ?

OpenStudy (anonymous):

@DLS

OpenStudy (dls):

idk it has to be done that way only calculate no. of moles from latter info and put that value in n=g/m

OpenStudy (anonymous):

hav u did it

OpenStudy (anonymous):

@surdawi

OpenStudy (anonymous):

1L OF 0.50 N of NaOH requires NaOH = 20g 60 L of 0.50 NaOH requires NaOH = 20 x 60= 1200 g = 1.2 kg. 88 g NaOH is obtained from wet sample = 100g therefore 1 kg of NaOH is obtained from a wet sample 100/88 x 1.2= 1.364 kg

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