Question

What is the solution to the equation 9^(x + 2) = 27 ?

Answer 1

It is\[9^{x+2}=27\]?

Answer 2

hint : 9=3^2
27=3^3

Answer 3

@Aylin yes!

Answer 4

\[9^{x+2}=9^{x} \times 9^{2}\]if that helps

Answer 5

any of these @Aylin ?
x = 2.5

x = 0.5

x = –0.5

x = –3.5

Answer 6

I can't give you the answer, but I can help you work towards it.

Answer 7

\(\huge 9^{x+2}= 3^{2(x+2)}=3^3\)
now just equate the exponents!

Answer 8

after equating the exponents, you get
2(x+2) =3
can you solve this for 'x' ?

Answer 9

Because when the bases are same we can equate exponents :)

Answer 10

Yes :)

Answer 11

im really confused

Answer 12

which step ?

Answer 13

all of it

Answer 14

First equal the bases

\(\Large{{9^{(x+2)}=3^3}}\)
\(\Large{(3^2)^{(x+2)}=3^3}\)
gt it through here ??

Answer 15

@Kristy143SIO ??

Answer 16

@Kristy143SIO are u here ??

Answer 17

yes

Answer 18

\(\Large{3^{2x+4}}=3^3\)

now only equate the exponents

2x+4=3

Answer 19

ok?

Answer 20

solve this equation :)