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Mathematics 14 Online
OpenStudy (anonymous):

How do you find the y-intercept of h(x) in h(x)=x^2-16/x-4?

hartnn (hartnn):

to find the y-intercept , put x=0 in that equation, what you get ?

OpenStudy (anonymous):

But how does it work when one function is over the other one?

hartnn (hartnn):

just put x=0 in that equation!

OpenStudy (anonymous):

So I put it in both of them

hartnn (hartnn):

yes, h(0) = (0-16)/(0-4) =.... ?

OpenStudy (anonymous):

(0,4)

hartnn (hartnn):

thas your y-intercept, correct! :)

OpenStudy (anonymous):

Okay thank you that helped alot

hartnn (hartnn):

welcome ^_^

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