Question

First to get correct answer gets a fan and medal! A batter hits a baseball upward with an initial speed of 96 feet per second. After how many seconds does the ball hit the ground? Use the formula h = rt − 16t2 where h represents height in feet and r represents the rate in feet per second

Answer 1

Hint:

r = rate in feet per second = 96 and h = time to hit the ground = 0 so:

0 = 96t - 16t^2

Solve for t

Answer 2

how do you solve for the t squared?

Answer 3

0 = -16t^2 + 96t

factor out -16t to get:

0 = -16t(t - 6)

Finish solving for t

Answer 4

how would you do that?

Answer 5

Use the multiplication rule ab = 0 :
Either a = 0, or b = 0

So either -16t = 0 or t - 6 = 0

Answer 6

so then it would be 0=-16t(0)
but when you multiply anything times zero your answer is zero isn't it?

Answer 7

How do you solve

t - 6 = 0 ?

Answer 8

t=6

Answer 9

so is that right?

Answer 10

Yes, correct

The time the ball hits the ground is 6 seconds.