Question

I just wanted to know how to solve a system of equations when there is 3 equations. I don't want the answers I just want to know how to do it

Answer 1

You will be suspended from school if you are trying to get the answers.

Answer 2

@Deepcobra17 If you need help post your question one by one rather than writing connections algebra 2 students and stuff please.

Answer 3

I just wanted to know how to solve a system of equations when there is 3 equations. I don't want the answers I just want to know how to do it

Answer 4

@Deepcobra17 You would have simply posted that rather than saying [CONNECTIONS ACADEMY AND STUFF]

Thanks a lot for understanding :)

Answer 5

the same methods used to solve 2 equations are used to solve 3

Answer 6

I asked my math teacher and he doesn't want to help so I figured other people from that school could explain it better then he could. But it's okay, I'll go watch a YouTube explaining video or something

Answer 7

So I can use elimination?

Answer 8

you can; use one equation to eliminate a variable in the other 2; then you can eliminate again using the modified equations

Answer 9

a specific problem to work thru would help alot :)

Answer 10

-3x - 4y -3z = -7
2x -6y + 2z = 3
5x - 2y + 5z = 9

Answer 11

since the y parts all have a common factor; those look to be the simplest to eliminate to start with to me; what is your idea?

Answer 12

-3x - 4y -3z = -7
2x -6y + 2z = 3
5x - 2y + 5z = 9 <-- use this to elimiate the ys with


-15x + 6y -15z = -27
2x -6y + 2z = 3
----------------------
-13x -13z = -24


-10x +4y - 10z = -18
- 3x - 4y - 3z = - 7
--------------------
-13x -13z = -25

Answer 13

the modified results look to me like they have no common solution

so the overall system is inconclusive

Answer 14

Hold on, I'm still stuck on the first step

Answer 15

tell me where you are stuck at

Answer 16

How you got -15 + 6y

Answer 17

notice the 3rd equation has a -2y in it; and the others have a 6 and a 4 ... i used multiples of the 3rd equation to eliminate the y parts in the other 2

Answer 18

3rd eq: 5x - 2y + 5z = 9

times -3 to get -15x +6y -15z = -27

i multiplied it by -2 for the other one

Answer 19

Oh okay, I think I understand now

Answer 20

the modified results, if i did the mathing right :) appears to be parallel planes (or lines or whatever you want to call them) that never meet

Answer 21

Ok, so would I then Plug in the values to solve for x, y, and z?

Answer 22

Never mind I just worked it out on paper, thank you so much!

Answer 23

youre welcome, and good luck. as i see it, there is no solution to the system