Question

If ON = 8x – 8, LM = 7x + 4, NM = x – 5, and OL = 3y – 6, find the values of x and y for which LMNO must be a parallelogram. The diagram is not drawn to scale. pic and medal :)

Answer 1

Did you copy the x's and y's correctly?

Answer 2

i copy and paste, so yeah, lol

Answer 3

For the figure to be a parallelgram, the opposite sides must be equal.
So 8x-8=7x+4 => x=12
3y-6=x-5 => 3y=12-5+6=13 => y= 13/3

Answer 4

Are you sure that both ON and LM only have x's in them?

Answer 5

Guess it is not an exercise on system of equations.

Answer 6

So
x=12, y=13/3

Answer 7

Ok, forget it. I copied it wrong. I was getting a negative side length, but now I see why.

Answer 8

awesome, thanks guys

Answer 9

yw! :)

Answer 10

Look at your second equation. It's wrong. It should be
\( \bf x - 5 = 3y \color{red}{-} 6\)

You have 3y + 6 on the right side.
The way you have it, y = 1/3.
The correct way, y = 13/3.
In other words, you solved your second equation correctly. It's just that your second equation is not the correct second equation.

Answer 11

It is a parallelogram. ON=LM and NM = OL


Find x:
8x - 8 = 7x + 4
x - 8 = 4
x = 12

Find y:
x - 5 = 3y - 6
12 - 5 = 3y - 6
7 = 3y - 6
13 = 3y
13/3 = 3y/3
y = 13/3