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Calculus1 11 Online
OpenStudy (anonymous):

y=-1/√(x^2+1), then dy/dx=

OpenStudy (raden):

use the chain rule

OpenStudy (raden):

y = - 1/√(x^2+1) = - (x^2 + 1)^(-1/2) now, u can integrate it by chain rule

OpenStudy (anonymous):

Thanks! I got it now!

OpenStudy (raden):

really, what ur answer :)

OpenStudy (anonymous):

x/((x^2+1)^(1/2))

OpenStudy (raden):

i got different

OpenStudy (anonymous):

well with the chain rule I got 1/2(x^2+1)^(1/2)(2x) then I simplified

OpenStudy (raden):

in bracket, it should the power is 3/2 not 1/2

OpenStudy (anonymous):

why?

OpenStudy (raden):

i meant like this : |dw:1357183644901:dw|

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