Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (sammietaygreen):

y < –2

OpenStudy (anonymous):

-You know it is going to be a dotted line because y cannot equal -2 -You know it is going to be a horizontal line at y = -2 -You know everything below this line will be shaded because y is equal to every number that is less than -2 Now what do you think the answer is?

OpenStudy (sammietaygreen):

It's B or A but I think it's B.

OpenStudy (anonymous):

Why not A?

OpenStudy (anonymous):

the shaded region means that everything in this region is a possible answer. So is 0 a possible answer? no. The answer is B

OpenStudy (sammietaygreen):

Yeah. That's what I thought.

OpenStudy (anonymous):

For these types of problem try to think about what it means to say y is less than -2. That helps me

OpenStudy (sammietaygreen):

Could you help me on one more?

OpenStudy (anonymous):

sure

OpenStudy (sammietaygreen):

A local citizen wants to fence a rectangular community garden. The length of the garden should be at least 110 ft, and the distance around should be no more than 380 ft. Which system of inequalities and graph represents the possible dimensions of the garden? (1 point)

OpenStudy (anonymous):

This is a little tricky. Lets try to setup the equations first

OpenStudy (anonymous):

1) Length >= 110 ft length is the y axis so this is another horizontal line at y = 110. Also we know there will be a shaded region above this line. We can already throw out C and D

OpenStudy (anonymous):

2) Perimeter <= 380 ft 2L + 2W <= 380 ft This is the tricky part Looking at B I can tell it is wrong because the shaded region goes on forever. Remember that the shaded region is possible solutions. And (300, 300) is not possible because 1200 is not less than 380. The answer must be A

OpenStudy (sammietaygreen):

Thanks! I have 6 more problems like this. Ugh. Algebra *sigh*

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!