Question

help solving this quadratic >.>

Answer 1

Sure.

Answer 2

\[\LARGE \sqrt{\frac{\lambda}{2} + \frac{1-\lambda }{2}+5}=5\]

Answer 3

1) squaring both sides

Answer 4

lamda/2 gets cancelled :P
no lamda in the equation
no solution

Answer 5

because sqrt{1/2+5} can never =5

Answer 6

Yeah lol :P

Answer 7

dahell

Answer 8

oh sorry guys :P

Answer 9

http://bit.ly/UlJTI6 have fun

Answer 10

\[\LARGE \sqrt{\frac{\lambda^2}{2^2} + \frac{(1-\lambda )^2}{2^2}+5}=5\]

Answer 11

lol

Answer 12

@hartnn @hba

Answer 13

1) squaring both sides

Answer 14

\[\LARGE \frac{\lambda^2}{4}+\frac{1}{4}+\frac{\lambda^2}{4}-2 \frac{1-\lambda}{2} -5=25\]

Answer 15

Now take lcm

Answer 16

\[\LARGE \frac{\lambda}{2}+\lambda-6+\frac{1}{4}=25\]

Answer 17

\[\Huge{\sqrt{\frac{\lambda}{2}+\frac{1-\lambda}{2}+5}=5}\]\[\Huge{\sqrt{\frac{\lambda +1- \lambda}{2}+5}=5}\]\[\Huge{\sqrt{\frac{1}{2}+5}=5}\]\[\Huge{\sqrt{\frac{11}{2}}=5}\]By squaring both sides\[\Huge{\frac{11}{2}\ne25}\]Hence, no solution.

Answer 18

\[2\frac{\Lambda}{4}+4\lambda/4-\frac{125}{4}=0\]