Question

x(d^2y/dx^2)+dy/dx=1

Answer 1

\[x \frac{ d ^{2}y }{ dx ^{2} }+\frac{ dy }{ dx }=1\]

Answer 2

forgot to say where \[\rho=\frac{ dy }{ dx }\]

Answer 3

i am getting \[y=x+c _{1}Inx+c _{2}\] am i on the right track?

Answer 4

firstly its the linear form of diff....eauation that will be used

Answer 5

explain further what do u mean by that

Answer 6

which approach did u use to solve the question.. i mean the method.

Answer 7

i used substitution p=dy/dx and d^2x/dx^2=dp/dx

Answer 8

what do u think @nubeer

Answer 9

first solve \(x\rho'+\rho=1\) for \(\rho\) then solve \(dy/dx=\rho\)

Answer 10

@Moyo30 Actually, you got it right :\

Answer 11

yep, divide through by x and get \[\frac{ d \rho }{ dx}+\frac{ \rho }{ x }=\frac{ 1 }{ x}\]

Answer 12

Thx @Callisto

Answer 13

Welcome.. I didn't help though!!

Answer 14

u answered my question.

Answer 15

all i wanted to know was am i on the rite track

Answer 16

:)