Find all solutions to the equation. cos2x + 2 cos x + 1 = 0
i dont understand
Do you know a formula for cos2x?
Like cos2x = 2cos²x-1 ?
no but i know cosx= (1/secx)
If you replace cos2x with 2cos²x-1, you have a quadratic equation, with cosx as variable.
ok..
error, my bad. cos^(2)x + 2 cos x + 1 = 0
OK, so you already have a quadratic equation in cosx: \[(\cos x)^2 + 2\cos x +1 = 0\] If you like you could temporarily set p=cosx to get:\[p^2+2p+1=0\]Could you try to solve that one?
im stuck at p^(3)=-1/2
How do you get p^3 ?
@Lauren01 is it cos^2 x or cos 2x
This is the form you can use: (p+...)(p+...)=0. You must have done that before, I guess. Just look for the numbers on the dots: their sum is 2, their product is 1. They are not difficult to find...
@Yahoo! It is cos²x, @Lauren01 already mentioned...
oh...Sorry ...Did nt See !
We're waiting for Lauren01 to make a move.. ;)
sorry i got distracted by the office. its pie. because x=-1 is on Pie. (unit circle)
(p+1)(p+1)=0 cosx+1=0 cosx=-1 using the unit cirle x=-1 is on Pie.
Well done! BTW, aren't you supposed to give more answers, like x=pi+2k*pi, or do you have to solve only for x in [0,2pi]?
only one is fine
OK, next prob!
lol do you wanna do all my homework? lmao
Now you do your homework, then I'll only help you along...
lol goood choice
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