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HELP!! Factor if possible. Check by substituting x=1. 5t^2 + 7t + 2 Answer: (5t + 2) (t+1) -> how they got this?
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Dunno 5
5 t^2 + 5t + 2t + 2
as 7t can also be written as 5t + 2t
\[5 t^2 + 2t + 5t + 2\]
But what was the method used to get the answer though? ):
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taking t common in \[5t ^{2} + 2t\] we get t ( 5t +2 )
taking 1 common in next two terms we get 1( 5t+2)
so roots are (5t+2) and (t+1) respectively
this is a factor method to find roots
so roots are t = -1 and t = -2/5
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