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Mathematics 14 Online
OpenStudy (anonymous):

HELP!! Factor if possible. Check by substituting x=1. 5t^2 + 7t + 2 Answer: (5t + 2) (t+1) -> how they got this?

OpenStudy (anonymous):

Dunno 5

OpenStudy (anonymous):

5 t^2 + 5t + 2t + 2

OpenStudy (anonymous):

as 7t can also be written as 5t + 2t

OpenStudy (anonymous):

\[5 t^2 + 2t + 5t + 2\]

OpenStudy (anonymous):

But what was the method used to get the answer though? ):

OpenStudy (anonymous):

taking t common in \[5t ^{2} + 2t\] we get t ( 5t +2 )

OpenStudy (anonymous):

taking 1 common in next two terms we get 1( 5t+2)

OpenStudy (anonymous):

so roots are (5t+2) and (t+1) respectively

OpenStudy (anonymous):

this is a factor method to find roots

OpenStudy (anonymous):

so roots are t = -1 and t = -2/5

OpenStudy (anonymous):

Oh, alright thank you!

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