X=20
I need to show my work though....
Since angles A and C are along a diagonal of the parallelogram, they are supplementary. Hence: m<A + m<C = 180 ==> (5x - 20) + (3x + 40) = 180.
Okay so am I done with just that?^
its supposed to be m<C=3x+40.
Yep i knew that and thats all you need
@beautiful_gurl In a parallelogram, consecutive angles such as <A and <B, or <B and <C, are supplementary. This is not what you have in this problem. In a parallelogram, opposite angles are congruent. Since the parallelogram is called ABCD, and the vertices are always named in order, angle A and angle C are opposite angles, and, therefore, congruent. That means m<A = m<C Since m<A = 5x - 20 and m<C = 3x + 40, then 5x - 20 = 3x + 40 2x = 60 x = 30
how do I show the work for that?
I just did. Start with m<A = m<C, and continue from there.
how?
m<A = m<C m<A = 5x - 20, m<C = 3x + 40 5x - 20 = 3x + 40 2x = 60 x = 30
okay thanks
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