Question

What is the center and radius of the circle with the equation x2 + y2 + 8x + 4y – 61 = 0

Answer 1

center is (-4,2) with radius 9

Answer 2

@FlyinSolo_424 http://openstudy.com/study#/updates/4fc79d25e4b022f1e12f0873

Answer 3

whats that link

Answer 4

youll see

Answer 5

its the awnser

Answer 6

ohhhhhhh

Answer 7

x^2 + y^2 + 8x + 4y - 61 = 0
You need to complete the square for both x and y.
(x^2 + 8x + ) + (y^2 + 4y + ) = 61
(x^2 + 8x + 16) + ( y^2 + 4y + 4) = 61 + 16 + 4
(x + 4)^2 + (y + 2) = 81
(x + 4)^2 + (y + 2)^2 = 9^2
Center: (-4, -2), radius = 9

Answer 8

Basically get the 'x' terms & 'y' terms together comp,letetetete the square whaen everythings = to1 GL ;D