Melinda's lights went out. She has 3 pairs of red socks in her drawer, 2 pairs of black socks, and 5 pairs of white socks. What is the minimum number of pairs she must remove from the drawer to ensure that she has a pair of each color? i got 7 but the website im using says the answer is 9. how do you work this problem? i took one from each pair then added up 2,1, and 4.. is this the wrong way to work this problem?
First, i think Melinda needs some new lights. http://www.bulbs.com/Light_Bulbs/results.aspx?cm_mmc=Google-_-NonBrand-_-Bulbs-_-light%20bulbs&adpos=1t2&creative=16392895638&AffID=6 this should help her.
yea tell the people making the TEAS test that one..
jim, i think the people who made the practice test questions are wrong! lol im using this website http://www.testprepreview.com/modules/mathematics2.htm
Best Case Scenario: You pick 3 socks (one of each color). So first sock may be red, then the next may be black, and the third may be white. Worst Case Scenario: She picks all 5 white socks first. So she has only picked one color so far. Then she picks all 3 red socks as the next group. So she has picked 8 so far. She's gotten 2 colors, but she needs 3 colors. So she needs to pick one more color to guarantee that she gets all 3 colors Of course she can pick any number of socks and she *may* get 3 different colors. However, there's no guarantee that she'll pick 3 different colors until you consider the worst case scenario. Once you do, you can be certain that somewhere in those 9 socks will be 3 socks of 3 different colors.
is there some kind of formula to be working for these types of questions?
not really, but you can try all possible scenarios (you may be there a while though...)
that's why I only laid out the best and worst case scenarios
well this test is timed so will that just waste time doing that way?
yes because there are roughly 362 thousand scenarios, but if you can see how I'm getting the best and worst case scenarios, then you'll save a ton of time
best case scenario = smallest amount of socks taken out with 3 diff colors worst case scenario = largest amount of socks taken out with 3 diff colors
is there a way to plug in the answers from the multiple choice to basically guess n check
that trick is only useful if you have a formula to work with
you don't have a formula here, just concepts really
ok could you reexplain how to find the smallest and biggest amount??
maybe word it differently lol
por favor
please*
ok the best case scenario is where you pick 3 socks and you get 3 different colors (and you know this for sure) make sense?
basically, the better the scenario, the less you have to work and pull out socks (ie you take less time and energy)
with me so far?
ok so when i read the problem i first think i need to find the best case right? and how do i do that
im still confused on finding the scenarios
you want 3 different colors, so you need to pick 3 socks since they are each one color
the best case is that you do the least amount of work and spend the least amount of time doing it so that means that picking 3 socks is the best option...ie you're hoping this will happen but...there's no guarantee that it will happen
it's just one case out of 362,880 cases total...which is a lot i know, but there's good news you can find the worst case scenario and use that to find the answer you want 3 different colors, so you want each sock to be different But what if you pick all 5 white socks, then 3 red socks. You've picked 8 socks but only 2 colors so far, which means you need to pick one more (to get 9 total) to get 3 different colors This is the worst case scenario because it has you doing the most work
If you take out 8 pairs of socks its still possible not to have a pair of every color (you can have all the white and red, but no black) once you get the 9th pair, no matter how you try to pick them, you will always end up with one of each color.
Note in this problem you are not picking individual socks, but pairs. a pair is one object.
oh true, pairs not singles, but think of these socks as general objects (like blocks or pens)...it doesn't matter what they are, just that they're different colors
mkay still kinda in the clouds with this problem but i have to move to the next problem. thanks for the help
maybe it will help if you do this with some objects that are around you (eg: different colored pens)?
i guess im lost bc there really isnt a formula to plug in numbers
this is just one of those problems where you have to think about it in everyday terms and not use a rigorous formula
Which of the following fractions are correctly placed from the least in value to the greatest in value? A. 1/4, 17/25, 3/4, 11/16 B. 17/25, 1/4, 11/16, 3/4 C. 1/4, 17/25, 11/16, 3/4 D. 1/4, 17/25, 3/4, 11/16 E. 3/4, 17/25, 11/16, 1/4 for this problem what is the quickest way to find the answer since the test is timed with i think 34 questions
but you can see that the worst case comes from adding up the larger numbers first: 5, then 3, then adding 1 you don't add 5 then 2 or 2 then 3, and so on
can you use a calculator?
no calcs
ok you'll have to get each fraction to have a common denominator
we have the denominators: 4, 16, 25 they all need to be the same in order to compare the fractions
that just seems so timeful lol
hmm let me think of a shortcut
you agree that 1/4 is less than 3/4 right?
yes
so that allows you to rule out choice E
ok i see
25 is close to 24, so a quarter of this is 24/4 = 6 so 6/25 is close to 1/4 (not exactly 1/4, but close enough) this means that 11/25 must be bigger than 1/4 since 11 is bigger than 6
oh i meant 17/25, not 11/25
so there's no way choice B is true, which means we can eliminate that too
so that leaves A, C, and D btw, choices A and D are identical is that a typo?
must be but thats how they have it
so the only thing left to compare is 3/4 and 11/16 to see which is bigger
if you multiply top and bottom of 3/4 by 4 to get 12/16 so this shows that 3/4 is bigger than 11/16 (since 12/16 > 11/16)
so that eliminates A and D (which strangely are the same) leaving C as the only answer
oh i just messaged u
im on to another problem haha
ill post it so i can give u credit for ur hard work
alright lol
no its fine, i don't really care about the medals to be honest
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