Question

Find an antiderivative F of f(x) = x^2*sin(x^2) such that F(1) = 0.

Answer 1

I don't think you can use u-sub here. cuz then it'd be f(u) = u*sinu..

Answer 2

and i haven't learned trig sub or integration by parts yet.

Answer 3

jenny you are a liar i think

Answer 4

-_-
i haven't.
but i can do integration by parts. but my teacher never taught it.

Answer 5

becos that problem required fresnal integral

Answer 6

what?

Answer 7

Use \(u = x^2\). Then \(x = \sqrt{u}\)

Answer 8

u can use u sub on that

Answer 9

\[f(x) = x^2\sin(x^2) \]

Answer 10

if u = x^2 then du = 2xdx

Answer 11

well what method are you allowed to use if you can't use trig or parts

Answer 12

that's what i don't understand.
u-sub doesn't really work...

Answer 13

so ur on u-sub section of the book?

Answer 14

no it's a review packet. i learned area, u-sub, trapezoid rule, and simpson's rule

Answer 15

thats the way it is

Answer 16

not an exponent

Answer 17

no it's
\[f(x) = x^2\sin(x^2)\]

Answer 18

This isn't a candidate for u sub.

Answer 19

u = x^2
du = 2x dx cant use u du sub

Answer 20

no place to apply a substitution

Answer 21

\[
\frac{1}{2}\int \sqrt{u}\sin(u)du
\]Isn't helpful.