calculate volume in liters of oxygen gas needed to produce 700 liters of dinitrogen trioxide so confused

Question

anonymous · Answer

Dinitrogen trioxide, N2O3. 
density = 1.4 gr/ml (liquid), 1.783 gr/ml (gas), molar mass 76.01 gr/mol
Oxigen O2
density = 1.429 gr/liter at 0 celcius and 101.325kpa.

700 liters N2O3 TIMES a thousand to become mililiters (ml) because we have liquid density of N2O3 in ml.
volume N2O3 in ml TIMES N2O3 liquid density to eliminate the ml, then you have only gr of N2O3.
mass of N2O3 DIVIDED by N2O3 molar mass to get moles of N2O3.
moles of N2O3 TIMES 3 because you have 3 atoms of oxygen in the molecule
moles of oxygen TIMES oxygen molar mass to get oxygen mass in gr
oxygen mass in gr DIVIDED by oxygen liquid density to get liters of oxygen gas.

aaronq · Answer

write a balanced equation, find how many moles of O2 are needed based on coefficients. done

aaronq · Answer

ps 1 mole of gas (ideally) = 22.414 L