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OpenStudy (anonymous):
if A & B are second quadrant angles such that sinA=2/3 & cosB=-1/2, find
(a) sin(A+B)
(b) cos(A+B)
(c) tan(A+B)
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OpenStudy (anonymous):
ok what you need are the following numbers:
\(\cos(A)\) and \(\sin(B)\) so you can use the various formulas
do you know how to get them
OpenStudy (anonymous):
uhh you would use pythagorean ?
OpenStudy (anonymous):
for \(\sin(A)=\frac{2}{3}\) i would
for \(\cos(B)=\frac{1}{2}\) i would know instantly that \(\sin(B)=\frac{\sqrt{3}}{2}\)
OpenStudy (anonymous):
\[\cos(A) = \frac{ \sqrt{5} }{ 3}\]
OpenStudy (anonymous):
then i would use the equation\[\sin(u+v)=\sin u \cos v + \cos u \sin v\]
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OpenStudy (anonymous):
?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
wait... if angle B is a second quadrant angle, then shouldn't cos(B) = negative?
OpenStudy (anonymous):
@Byteme good point !
OpenStudy (anonymous):
oh ... sorry i meant it to be -1/2
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OpenStudy (anonymous):
oh ok good
still the same sine though
but \(\cos(A)=-\frac{\sqrt5}{3}\)
OpenStudy (anonymous):
ye. so id substitute each to the sum & difference formulas?
OpenStudy (anonymous):
yep...
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