Question

How to solve x^2 – 10x = –13?

Answer 1

The choices are
5 ± 2√3
5 ± √38
5 ± 2√2
5 ± 3√2
but i dont just want an answer i need help on how to do the problem.

Answer 2

complete the square by writing
\[(x-5)^2=-13+25=12\] then take the square root

Answer 3

\(\LARGE{x^2-10x+13=0}\)
Here, a=1, b=-10, c=13.

use the quadratic formula\[\LARGE{x={-b \pm \sqrt{b^2-4ac} \over 2a}}\]
\[\LARGE{x={-(-10) \pm \sqrt{(-10)^2-4(1)(13)}\over 2(1)}}\]

Answer 4

Add 13 to both sides and set it equal to zero.
use quadratic formula to solve:
\[\frac{ - b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 5

Plug it in where \[ax^2 + bx + c = 0\]

Answer 6

Solve this equation for 'x' :)

Answer 7

Ok i think i have a better understanding.

Answer 8

When I work out whats in the radical i get an irational number what do i do?

Answer 9

Factor the number in the radical. If you have any factor repeated twice, pull it out.

Answer 10

What i got was 4*1=4
4*13=52
-10^2=100
100-52=48
then i forget how to factor the number from there