Question

solve the trig identities in a single trig function: could you help me!!?? http://bamboodock.wacom.com/doodler/50e89ae1-6dbc-46c5-b145-b878b601ef5a

Answer 1

the mistake here is that \(1-\cos(x)\neq \sin(x)\)

Answer 2

\(1-\cos^2\theta=\sin^2\theta\)
\(\sin\theta=\sqrt{1-\cos^2\theta}\)

Answer 3

you actually have to add the fractions first

Answer 4

\[\frac{1}{1+\cos(x)}+\frac{1}{1-\cos(x)}=\frac{1+\cos(x)+1-\cos(x)}{(1+\cos(x))(1-\cos(x))}\]

Answer 5

now the numerator is 2, and the denominator is \(1-\cos^2(x)=\sin^2(x)\)

Answer 6

But I see that the question doesn't say \(\dfrac{1}{1 + \cos(x)} + \dfrac{1}{1 - \cos(x)}\)