Question

Find the area between the curves y^2=x and 3y^2=4-x

Answer 1

by integral ?

Answer 2

yes by integral..

Answer 3

u have to determine the intervals for integral. they are can be found by intersection of that curves

Answer 4

y^2 = x -------> x=y^2 ... (1)
3y^2=4-x ----> x=4-3y^2 ... (2)
subtract (1) and (2) :
4y^2 - 4 = 0
y^2 - 1 = 0
(y+1)(y-1) = 0
for zeroes, y = -1 or y = 1

Answer 5

so, the area(A) = int [-1,1] (4-3y^2-y^2) dy A
= int [-1,1] (4 - 4y^2) dy
solve this integral ....

Answer 6

miss "A" of the last, a typo

Answer 7

I solved it , the Area = 16/3 square units .. ?

Answer 8

yes, i got it like u

Answer 9

thanks man :)

Answer 10

very welcome