A tank is holding 60 liters of a chemical solution. Currently, the solution has a strength of 30%. How much 70% solution must be added to the tank to get a final strength of 40%?

Question

anonymous · Answer

man those hits just keep coming

anonymous · Answer

haha I'm sorry but I'm serious when I say I am horrible at math ..

anonymous · Answer

you have 60 liters that is 30% solution, so at the the start you have $.3\times 6=1.8$ liters of solution

anonymous · Answer

if you add say $x$ liters  of 70% solution, it will have $.7x$ liters of solution, and you will have $60+x$ liters total, that you want to be 40% solutions

anonymous · Answer

therefore you can solve 
$$1.8+.7x=.4(60+x) $$ for $x$

anonymous · Answer

easier to multiply by 10 to get rid of the annoying decimal, and solve instead 
$$18+7x=4(60+x)$$

anonymous · Answer

still need help, or are you good from here?

anonymous · Answer

74?

anonymous · Answer

yup
guess you got this

anonymous · Answer

haha