Dividing Complex numbers (-5i)/2i. Please help!!!!!!!!!!!¡!¡!

Question

Dividing Complex numbers  (-5i)/2i.     Please help!!!!!!!!!!!¡!¡!

anonymous · Answer

I think you are over thinking this.  Treat the i's similar to variables.  What would you get if you had:
$$\frac{ -5x }{ 2x }$$

homeworksucks · Answer

shouldn't there be some sort of a+bi format? In that case, you take the conjugate-(opposite of bi as in pos-to-neg and vice versa) of the denominator(bottom number) of the fraction and multiply it to both the top and the bottom number and use FOIL. From there,  simplify and remember that i^2 is -1.

zehanz · Answer

If you write it like so:$$\frac{ -5i }{ 2i }$$then the i cancels, leaving you with -5/2.

zehanz · Answer

I've just got rid of two complex numbers!

hartnn · Answer

if you want a+bi format, it'll be -5/2 +0i.

anonymous · Answer

Yes, It should be -5/2 + 0i if expressed in the a+bi form.

zehanz · Answer

That would seem far fetched to me. Sometimes, calculations with complex numbers yield real numbers. 
It would be the same (IMO), if you are adding the fractions 1/2 and 3/2 and then insist on writing it as 4/2 instead of 2.