Question

Using elimination, substitution solve c and b

C. y = 1\2x - 6
2x + 6y = 19


B. 7x - 3y = 20
5x + 3y = 16

Answer 1

@hereweg0

Answer 2

okay solve the second one for y

Answer 3

so for elimination, i suggest multiplying the first equation by negative 4 to get rid of x, than solve for y.

for the substitution part, any one will work just fine, just isolate one variable

Answer 4

i'm so lost

Answer 5

inspy has it

Answer 6

i'm get that

Answer 7

7x - 3y = 20
5x + 3y = 16

To eliminate you add together the top and bottom equation so you get
12x = 36
x= 3
Then you can work out y
5x3 +3y = 16
15+3y = 16
3y= 1
y= 1/3

Answer 8

watch it though inspy, i think that was a .5x

Answer 9

The first one is wrong. I forgot to multiply the -6 by 6

Answer 10

y=.5x-6 and 2x+6y=19 so multiply the first eq by 4 to get:

4y=2x-24 = 4y-2x=-24 now take that and add the two to get:

10y=5 so y =1/2 then just solve for x using the known y-value

for the substitution:

remember from your first eq that y=.5x-6, so just sub that into the second eq: 2x+6(.5x-6)=19 and solve

Answer 11

y = 1\2x - 6
2x + 6y = 19

6y = 3x-36
6y= 19-2x
3x-36=19-2x
5x= 55
x= 11
y= -0.5

Thanks Mr Doe

Answer 12

de nada

Answer 13

i get it thanks you guys