Determine whether this series converges or diverges. If it converges find the sum (see contents of quest for series)
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OpenStudy (anonymous):
\[\sum_{n=1}^{\infty}\frac{ 1 }{ 2n(n+1)}\]
OpenStudy (abb0t):
Use one of the tests. When in doubt, use ratio test. Always works.
OpenStudy (abb0t):
Usually works*
OpenStudy (anonymous):
i am not sure of my working. i first split it into partial fractions then took the limit to infinity is that correct?
OpenStudy (abb0t):
According to ratio test:
\[L = \lim_{n \rightarrow ∞}\left| \frac{ a_{n+1} }{ a_n } \right|\]
Converges (ans converges absolutely) if L < 1
Diverges if L > 1
Use different test if L = 1
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OpenStudy (zzr0ck3r):
Partial fractions, then it looks as if its telescopic.
OpenStudy (anonymous):
partial fractions give me \[\frac{ 1 }{ 2n }-\frac{ 0.5 }{ n+1 }\]
OpenStudy (zzr0ck3r):
Yes thats it its telescopic. U understand?
OpenStudy (anonymous):
no, explain further
OpenStudy (anonymous):
AST works on series that alternates between positive and neagtive. is the above series alternating
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OpenStudy (zzr0ck3r):
OpenStudy (zzr0ck3r):
Converges to 1/2
OpenStudy (zzr0ck3r):
Understand?
OpenStudy (zzr0ck3r):
Use comparison to see it converges then do what i did to get the sum
OpenStudy (anonymous):
Thx
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OpenStudy (zzr0ck3r):
@Moyo30 understand?
OpenStudy (zzr0ck3r):
Np
OpenStudy (anonymous):
comparison test using which function to compare?
OpenStudy (zzr0ck3r):
1/n^2
OpenStudy (anonymous):
thx, i have to go away. will look @ it when i come back.