Question

@ParthKohli @hartnn first of all give me a revision on quadratic equations & give me some tips on them so i can write notes on them & then tell me a site where i can gt a lot of question on quadratic equation :)

Answer 1

Paul's Notes and Khan Academy!

Answer 2

I know khan academy but what is the site for paul's notes ?

Answer 3

@ParthKohli is there any google search for them

Answer 4

http//khanacademy.org
http://tutorial.math.lamar.edu

Answer 5

http://khanacademy.org *

Answer 6

How could I forget AoPS?

Answer 7

Wait, take a look at the videos.

Answer 8

well nice ntes on paul maths notes but wht is aops

Answer 9

One second...

Answer 10

http://www.artofproblemsolving.com/Videos/index.php?type=introalgebra#chapter10

Answer 11

I bet this will be enough for ya :)

Answer 12

ya & patrickJMT.com is also best :)

Answer 13

Yup, that guy is really great!

Answer 14

I want his Sharpies. :P

Answer 15

You can use AoPS Alcumus for practicing: http://www.artofproblemsolving.com/Alcumus/Introduction.php

Answer 16

sharpies=?

Answer 17

The pens he uses.

Answer 18

haha , i want his pages he rubs his mistakes with his hands :)

Answer 19

Haha yes. :p

Answer 20

^_^

Answer 21

Just take a look at AoPS videos -- the man who did the videos also sometimes, dresses as a black sweater guy who uses tricks to solve problems.

Answer 22

ok!

Answer 23

Well ,

The first step is to convert it to the standard form of Quadratic equation.

Which is,

\[\huge\ ax^2+bx+c=0\]

You should also keep in mind the Quad formula.

\[\huge\ x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

There are some other methods to solve the Quad equations.

Which are mentioned below,

1)Breaking the middle term.

2)Completing the whole square method.

Answer 24

Do you need the derivation of Quadratic Formula? @jiteshmeghwal9 =)

Answer 25

I'd just write it down.\[ax^2 + bx + c = 0\]Multiply \(4a\) to both sides.\[4a^2x^2 + 4abx + 4ac = 0\]Subtract \(4ac\) from both sides.\[4a^2x^2+ 4ab = -4ac\]Add \(b^2\) to both sides.\[4a^2x^2 + 4ab +b^2= b^2 - 4ac\]Now completing the square,\[(2ax + b)^2 = b^2 - 4ac\]Square root\[2ax + b = \pm\sqrt{b^2 - 4ac}\]\[2ax = -b \pm \sqrt{b^2 - 4ac}\]\[\boxed{x = \dfrac{-b\pm \sqrt{b^2 - 4ac}} {2a}} \]

Answer 26

I know the quadratic equation's derivation. It's easy. i have a tutorial on this also :)

Answer 27

Nice!

Answer 28

well, paul's notes are very interesting :)

Answer 29

They are, yes :D

Answer 30

when i wrote the tutorial @lgbasallote asked me so tough questions on that i totally confused on that so i asked u for the notes

Answer 31

now i'm going log out & the viper is coming online, bye :)