Question

y=(3x+2)(5x+1)^{4} <------

Answer 1

wats the question

Answer 2

\[\frac{dy}{dx}\]?

Answer 3

yes

Answer 4

use product rule
\[(fg)^{'}=f^{'}g+fg^{'}\]

Answer 5

ok

Answer 6

\[\color{red}{ (3x+1)}(5x+1)^4+(3x+1)\color{red}{(5x+1)^{4}}\]
red once have to be derived

Answer 7

\[3(5x+1)^{4}+(3x+2)(20(5x+1)^{3})\]

Answer 8

am i there with the step1?

Answer 9

\[3(5x + 1)^{4} + (3x + 1)(20)(5x + 1)^{3}\]You were just slightly off with that first step.

Answer 10

You had a "3x + 2" in that second term instead of "3x + 1". Perhaps you were just making a typo?

Answer 11

lol i follow blinding from the guy expression

Answer 12

np :-)

Answer 13

how do i do the next step?

Answer 14

The final answer in these types of problems is usually given as factors, just like the problem expression. You would take out a factor of (5x + 1)^3 from each of the 2 terms.

Answer 15

\[(5x+1)^{3}(3(5x+1)+20(3x+2)\]

Answer 16

You're close. You're making that same mistake again though. That's "3x + 1", not "3x + 2". After you make that correction, just simplify everything in that big second factor.

Answer 17

my correct expression is 3x+2

Answer 18

(5x + 1)^3[3(5x + 1) + 20(3x + 1)]

(5x + 1)^3 times (75x + 23)

Answer 19

sorry if i had confuse you.. my question is y=(3x+2)(5x+1)^4

Answer 20

np. I'll start over with that equation.

Answer 21

(5x + 1)^3[3(5x + 1) + 20(3x + 2)]

(5x + 1)^3 times (75x + 43)

Answer 22

So, you had the first step right and I just went ahead and finished it off.

Answer 23

ooh i got it

Answer 24

http://openstudy.com/study#/updates/50e856dee4b06af148a06469
how about check this up for me?

Answer 25

Good work! Nice working with you! Good luck in all of your studies and thx for the recognition! @mathnoob1

Answer 26

thank you good luck to u 2