Solve the following formula for W: x=2W^2/Z
So you have:\[x=\frac{ 2W^2 }{ Z }\]It already help if you had:\[2W^2=...\] If you have trouble doing that, imagine you had\[6=\frac{ 18 }{ 3 }\]The you would know in an instant what to do to write it as:\[18=...\]
|dw:1357407836336:dw| I have this so far though?
Looks good! So now you have to get from w² to w...
Thats the part i dont know how to do
|dw:1357408781728:dw| IS IT RIGHT?
You mean take the root of xz/2? Then you are right!
Or do i keep the square\[\sqrt{XZ/2}^2\]d? \[\sqrt{XZ/2} =W\]
WAIT SO WHATS IS IT? D: i HAVE \[\sqrt{xz/2}\] I have this as an answer but i dont know if its right
Strictly spoken, there are two possibilities: \[W=\pm \sqrt{\frac{ xz }{ 2 }}\]To understand this, take a look at this: w²=16. What is w? Well, because 4²=16, w=4. But: (-4)²=16 as well, so w=-4 is also correct. There are two possibilities!
Thank you so much!!!!!!!!!
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