Which of the following is the solution to the equation 25^(z + 2) = 125 ? z = 5.5 z = 3.5 z = –2.5 z = –0.5
Take the natural log of the equation. HINT: \[\ a^n=ln (a)^n = n \ln(a)\] where 'a' is a constant.
Then, use algebra to rearrange and solve for z.
Could you work through the steps for me?
please?
I gave you a good amount of tip and hints. Try and work it out yourself first. If you are wrong, there are no penalties. I will help guide you in the right direction.
z= 5.5 ?
Am I right?
?
Not quite. How did you get that?
well I got down to z= 11/2
Your first step should be to take the natural log of everything and take the form: \[(z+2)\ln25 = \ln125\]
Your next step should be to divide by...
1n25 ? since its outside the parenthesis?
Correct! Now you have: \[z+2 = \frac{ \ln125 }{ \ln25 }\]
Now, what can you do next to solve for z?
add 2 to each side
Well, not add 2, but instead subtract. If you add 2 to both sides, you get z+4, and you're solving for z = #
oh, what do we do from there?
Subtract 2 from both sides and thats your answer. Plug it into a calculator to get your answer.
z= -2.5 ?
?
hello can someone confirm this???????????????????????????????????
\[25=5^2\] \[125=5^3\]
\[25^{z+2}=5^{2z+4}=5^3\] \[2z+4=3\] \[2z=-1\] \[z=-\frac{1}{2}\]
i have no idea what that log stuff was about, it is totally unnecessary
thanks, that makes more sense to me lol
Idk, I got -0.5 using log. Lol
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