Question

How do i verify 1+tan^3x / 1+tan^3x = 1-tanx+tan^2x

Answer 1

can you rewrite that using the equation editor?

Answer 2

Is this correct?
\[\frac{ 1+\tan^3(x) }{ 1+\tan^3(x) }= 1-\tan(x)+\tan^2(x)\]

Answer 3

that cant be right

Answer 4

\[\frac{ 1+\tan^3x }{ 1+\tan^3x } = 1-tanx + \tan^2x\]

Answer 5

o_o

Answer 6

ahh i made a mistakeee!

Answer 7

\[\frac{ 1+\tan^3x }{ 1+tanx } = 1-tanx + \tan^2\]

Answer 8

oh ok ! that one looks like an identity . the last one did not. abb0t looks like he is about to help

Answer 9

\[\tan^3(x) = \tan^2(x) \tan(x) = (\sec^2(x)-1)\tan(x)\]

Answer 10

i think i got it. ill try to figure this out by myself!!

Answer 11

okay...im really lost... ill draw it down what im doing so far