Question

@blondie16 Algebra Question

Answer 1

Simplify the expression:
\[\frac{ (x^2-4)^\frac{ 1 }{ 2 }3-3x \frac{ 1 }{ 2 }(x^2-4)^{-\frac{ 1 }{ 2 }}2x }{ \left[ (x^2-4)^\frac{ 1 }{ 2 } \right]^2 }\]

Answer 2

\[\frac{(x^2-4)^\frac{ 1 }{ 2 }(3)(x^2-4)^\frac{ 1 }{ 2 }-2x \sqrt{3} }{ (x-2)(x+2)(x^2-4)^\frac{ 1 }{ 2 } }\]

Answer 3

there....^^^^^^^^
i doubt thats right though... LOL xDxD

Answer 4

Not quite, but a good try. I can see how you got there.

Answer 5

aweh mann :(

Answer 6

lol maybe :P

Answer 7

This should be a standard question for algebra exam

Answer 8

answer is \[\frac{3}{\sqrt{x^2-4}}-\frac{3x^2}{(x^2-4)^\frac{3}{2}}\]

Answer 9

i got \[\dfrac{-12}{(x^{2}-4)^\dfrac{3}{2}}\]

Answer 10

\[\large{3x^2\over (x^2-4)^{3\over2}}+{3\over\sqrt{x^2-4}}\]

Answer 11

\(\huge \color{Hotpink}{\checkmark }\)

Answer 12

\[\huge\(3\sqrt{x^2-4}-\frac{ 3x^2 }{ x^2-4 })/(x^2-4)\]

\[\huge\ 3(x^2-4)^{3/2}-3x^2(x^2-4)\]

\[\huge\ 3x^3-24-3x^4+12x^2\]

\[\huge\ -3x^4+3x^3+12x^2-24\]

\[\huge\ -3(x^4+x^3-4x^2-8) < Answer\]

Answer 13

One thing i wanna say everyone gave a diffrent a solution, who's right ?

Answer 14

Well i guess i am right, i answered it right the last time.

http://openstudy.com/users/abb0t#/updates/50dca993e4b0d6c1d542f834

Answer 15

@hba what have you done ?? :P

Answer 16

he solved it correctly in that link..... but not in this post :P

Answer 17

\[\huge3\sqrt{x^2-4}-\frac{ 3x^2 }{\color{blue}{\sqrt{ x^2-4} }})/(x^2-4)\]

Answer 18

yes, no.

Answer 19

Nice \(\Huge{\color{green}{L}\space\color{red}{a}\space\color{purple}{T}\color{pink}{e}\space\color{blue}{X}}\) @hba ;)

Answer 20

Thanks :P

Answer 21

I didn't think you guys would try it :P thanks guize.
But I think raja has the correct answer.

Answer 22

Woot Woot!