Question

Would someone explain how to set this problem up?
Solve the equation:
log(8)x + log(11)x = 1

Answer 1

8 and 11 are in base?

Answer 2

yes

Answer 3

\[\Large \log_8 x + \log_{11} x =1\]
\[\frac{\log x}{\log 8} + \frac {\log x}{\log 11} = 1\]

Answer 4

thank you

Answer 5

so then what steps would allow me to solve for x ?

Answer 6

take lcm.

Answer 7

88 ?

Answer 8

\[\frac{ (\log x * \log11) + (\log x * \log 8)}{\log8 * \log11}=1\]

Answer 9

ok, ty!

Answer 10

so then x= 8, 11

Answer 11

Nope.

Answer 12

\[\frac {\log x (\log 11 + \log8)}{\log 88} = 1\]

Answer 13

ok, my problem asks:
x=
or there is no solution.

Answer 14

Solve for x.
\[\log x = \frac{\log 88}{\log11 + \log8}\]

Answer 15

Insert the values in a calc.

Answer 16

2.770