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Mathematics 14 Online
OpenStudy (anonymous):

\[\lim_{x \rightarrow \frac{ \Pi }{ 2 }} (cosx)^{cosx}\]

hartnn (hartnn):

use log. take log on both sides.

OpenStudy (anonymous):

ln y=cosx ln(cosx)

OpenStudy (anonymous):

cos x * log cos x (cosx / cos x) * -sinx + log cos x * - sinx

hartnn (hartnn):

what is this ?? (cosx / cos x) * -sinx + log cos x * - sinx

hartnn (hartnn):

you can use LH only if you have 0/0 or infinity/infinity form

OpenStudy (anonymous):

Huh..i Just Forgot that..)

OpenStudy (experimentx):

this is same as x^x x->0 try this x^x = e^(x log(x))

hartnn (hartnn):

so, log cos x/ sec x now try LH

hartnn (hartnn):

because cos =1/sec that should work, i think....

OpenStudy (experimentx):

that certainly works ... but this seems interesting ... using substitution. let cos(x) = u, then we have u -> 0 , u^u ... i think you might have done before.

hartnn (hartnn):

something like -sin /(sec cos tan) = -cos log L = 0 L=1

hartnn (hartnn):

you got 2 methods :) understood both ??

OpenStudy (anonymous):

Yup..)

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