Question

Mass of metal:15.363 g

Volume of water in the calorimeter:24.5 mL

Initial temperature of water in calorimeter: 25.2 °C

Temperature of hot water and metal in hot water bath:100.3 °C

Final temperature reached in the calorimeter:27.2 °C

1.Calculate the energy change (q) of the surroundings (water) using the enthalpy equation

qwater = m × c × ΔT.


We can assume that the specific heat capacity of water is 4.18 J / (g × °C) and the density of water is 1.00 g/mL. Show ALL your work.


The water has absorbed the heat of the metal. So, qwater = qunknown metal


2.Using the formula qunknown metal = m × c × ΔT, calculate the specific heat of the metal. Use the data from your experiment for the unknown metal in your calculation. Show ALL your work.

Answer 1

Plug all your given information.
i THINK, you might also need:

PV = nRT