Question

What is the derivative of 4^x lnx+x tanx+4e^x

Answer 1

\[\frac{ d }{ dx }a^x = a^xlog(a)\] \[\frac{ d }{ dx }ln(x) = \frac{1}{x}\]

Answer 2

would the + make the equation f+g+h?

Answer 3

that's correct! But in the question, you ALSO have

f(g)+h(i) + k

so you have to use product rule

Answer 4

so my answer would be f1(g)f(g1)+h1(i)h(i1)+k1? with 1 meaning prime

Answer 5

Yes, however, prime is written like this: f'
just to make it less confusing. But you got it down :)

Answer 6

you sir, are a genius and deserve a bueno!

Answer 7

just as a final confirmation my answer was (4^x log4 lnx)(4^x 1/x)+(tanx)(xsec^2x)+4e^x

Answer 8

Looks right to me.

Answer 9

thanks alot