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what are all the real zeros y = (x –12)^3 – 7
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I have done some of my work already but I am not sure if it is right :/
\[(x-12)^3=7\] \[x-12=\sqrt[3]{7}\] \[x=12+\sqrt[3]{7}\]
That is what I have, but what are the real zeros ?
that is the real zero
That's the answer ?
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there is only one real zero, and that is it
Oh okay. Thank you!
this thing crosses the \(x\) axis in only one place it looks just like \(y=x^3\) translated right 12 units, down 7
Yeah, I had the answer all along I guess. I just wasn't sure if this was the actual answer or not
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