Question

y=x^2-6x+2 . Explain how to identidy the vertex and two other points on the parabola. I also need to sketch it but i have no clue how

Answer 1

Start by completeing the square.

Answer 2

the quadrent?

Answer 3

Use: \[-\frac{ b }{ 2a }\]

Answer 4

then, plug it in to the quadratic.

Answer 5

i got -3

Answer 6

Now, plug it back in to get your y value.

Answer 7

f(-3)

Answer 8

so y=3^2-6(3)+2
-7?

Answer 9

Did you plug in 3 or (-3)?

Answer 10

oops 29 i did 3

Answer 11

it should be f(3), so recalculate the value of f(3) = ?

Answer 12

I got 29

Answer 13

-b/2a = -(-6)/2*1 = 6/2 = 3 right ?

Answer 14

lol yeah, I missed yeah the equation above

Answer 15

now, calculating again the value of f(3) = 3^2 - 6(3) + 2 = 9 - 18 + 2 = ?

Answer 16

the answer is -7?

Answer 17

correct

Answer 18

so thats my vertex?

Answer 19

so, the vertex is (3, -7)

Answer 20

ohhhh YAE!

Answer 21

How would you find 2 other pionts, just plug a # into the equation?

Answer 22

what do u meant " two other points" ?
is it the x-intercept and y-intercept ?

Answer 23

I think it wants me to find one point and the mirror image if it.

Answer 24

use wolfram :), ur sketch here :
http://www.wolframalpha.com/input/?i=y%3Dx^2-6x%2B2

Answer 25

but if u want do by manual, u have to determine the values of x-intercept and y-intercept also