Question

I need help simplifying this problem. 4y^3/3bk^2 - 5bx/6d^3k I got 1xy^3/3bd^3k but I think that is wrong.

Answer 1

well you need a common denominator of

6bd^3k^2

so the 1st term needs the numerator multiplied by 2d^3

and the 2nd term needs the numerator multiplied by bk

so you'll have

\[\frac{4y^3 \times 2d^3}{6bd^3k^2} - \frac{5bx \times bk}{6bd^3k^2}\]

Answer 2

\[\large{{4y^3 \over 3bk^2} \color{red}{\frac{2d^3}{2d^3}}- {5bx \over 6d^3k}\color{red}{\frac{bk}{bk}}}\]\[\large \frac{8y^3d^3-5xb^2k}{6bk^2d^3}\]

Answer 3

Thank you both of you all!

Answer 4

@ChmE do the variables have to be in order by alphabet or it doesn't matter?

Answer 5

it doesn't matter, the normal convention for algebra is in order but you can't be marked wrong if its not

Answer 6

Thank you so much @campbell_st