Rewrite with only sin x and cos x. sin 3x - cos x
sin 3x = ?
sin(x +2x)
Yes! We know that sin(a + b) = cos a sin b + cos b sin a. So now, what does sin(x +2x) equal to?
Also, note that sin(2x) = 2sin(x)cos(x) and cos(2x) = cos²(x) – sin²(x) = 1 – 2sin²(x) = 2cos²(x) – 1 You're welcome.
Sin(x)Cos(2x)+Sin(2x)cos(x)-cos(x)
Yeah, now replace sin(2x) to 2sin(x)cos(x) and cos(2x) to cos²(x) – sin²(x) or whatever you like to. You're done.
so sin(x)cos²(x)-sin²(x)+2sin(x)cos(x)cos(x)-cos(x)??
1) 2 sin x - sin3x - cos x 2) 2 sin x cos2x + sin x - 2 sin3x - cos x 3) 2 sin3x cos4x + 1 4) 3 sin x cos x - sin3x - cos x These are my 4 options and i don't seem to get any of them
??? The question says you have to rewrite the expression with only sin x and cos x.
My bad its actually 1) 2 sin x - sin^3(x) - cos x 2) 2 sin x cos^2(x) + sin x - 2 sin^3(x) - cos x 3) 2 sin^3(x) cos^4(x) + 1 4) 3 sin x cos x - sin^3(x) - cos x
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