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OpenStudy (anonymous):
NH3(g) + HCl(g) NH4Cl(s) how much product will be created by the complete conversion of .56 mol of NH3
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OpenStudy (matt101):
The reaction occurs in a 1:1:1 ratio. This means 1 mole of NH3 combines with 1 mole of HCl to produce 1 mole of NH4Cl. That means if you completely convert 0.56 mol of NH3, you produce 0.56 mole of NH4Cl.
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