Question

two triangles

left = perimeter =14 right=perimeter=21

Y Y 5/4Y 5/4Y


X 3X


(sorry, i cant put it the triangles)

Answer 1

okay so you can solve this by creating equations
for triangle 1: lets say that perimeter (p) = 2y + x =14

Answer 2

and triangle 2: p = 2 (5/4 y) = x

Answer 3

we can manipulate the equation for triangle 1
to be x= 14 -2y.
then substitute that into the equation for triangle 2
so the equation would be: 5/2y + 3( 14-2y) =21

Answer 4

k i got the first part but now i dont get how you got 5/2y+3(14-2y)=21

Answer 5

Left: x + y + y = 14
Right: 3x + (5/4)y + (5/4)y = 21

x + 2y = 14
3x + (10/4)y = 21 or 3x + (5/2)y = 21
Multiply 2nd eq by 2:
6x + 5y = 42

Now rewrite the two equations:
x + 2y = 14
6x + 5y = 42

multiply top eq by -6, and write second eq below:
-6x - 12y = -84
6x + 5y = 42

Now add the equations:
-7y = -42
y = 6
Now substitute y = 6 into original first eq:
x + 2y = 14
x + 2(6) = 14
x + 12 = 14
x = 2

Answer: x = 2, y = 6

Answer 6

Thank you!