Question

\[\lim_{x \rightarrow 0}[\frac{ e ^{tanx}-e^x }{ tanx - x }]\]

Answer 1

so just use l'hopitals

Answer 2

try that and then i can fix if you have more problems

Answer 3

i tried L-Hospital..it is werid...

Answer 4

d(e^tanx -e^x)/dx
e^tanx (sec^2 x) -e^x

Answer 5

d(tanx -x)/dx
sec^2 x -1

Answer 6

^ yup.

Answer 7

L'Hospital's, Chain Rule and Quotient Rule! I'd die doing this question O_O

Answer 8

But lim x--->0 sec^2 x-1 =0

Answer 9

Again use L'Hospital's Rule ???

Answer 10

sec^2 x-1 = tan^2 x

Answer 11

try using expressing in this form ... sorry don't have much time
http://www.wolframalpha.com/input/?i=lim+x-%3E0+%28e^x-1%29%2Fx

Answer 12

this is interesting