Question

infinite limit

Answer 1

\[\lim_{x \rightarrow \infty}\sqrt{9x ^{2}-x}-3x\]

Answer 2

i want to say negative infinity but i cant prove it

Answer 3

Try to Remove the radical

Answer 4

i dont want a final answer, i want to know how to do it.
so then its \[\left( 9x ^{2}-x \right)^{\frac{ 1 }{ 2 }}-3x\]

Answer 5

\[\sqrt{9x^2 - x}-3x * \frac{ \sqrt{9x^2 - x + }+3x }{ \sqrt{9x^2-x} +3x}\]

Answer 6

how about \[\frac{\sqrt{9x^2-x}-3x}{1}\times\frac{\sqrt{9x^2-x}+3x}{\sqrt{9x^2-x}+3x}\]

Answer 7

Lol..@sirm3d

Answer 8

is that multiplying by the conjugate?

Answer 9

Yup

Answer 10

@Yahoo! you click faster than me LOL

Answer 11

is it [\frac{ 9x ^{2}-4x }{ \sqrt{9x ^{2}-x}+3x }\]?

Answer 12

\[\frac{ 9x ^{2}-4x }{ \sqrt{9x ^{2}-x}+3x }\]?

Answer 13

i need an explanation, not the final answer

Answer 14

U should get