An initial population of 295 quail increases at an annual rate of 7%. Write an exponential function to model the quail population. What will the approximate population be after 2 years? (1 point)

A. f(x) = (295 x 0.07)^x;426
B. f(x) = 295(7)^x; 14,455
C. f(x) = 295(0.07)^x; 338
D. f(x) = 295(1.07)^x; 338

please help me!!

Question

An initial population of 295 quail increases at an annual rate of 7%. Write an exponential function to model the quail population. What will the approximate population be after 2 years?  (1 point)

A. f(x) = (295 x 0.07)^x;426
B. f(x) = 295(7)^x; 14,455
C. f(x) = 295(0.07)^x; 338
D. f(x) = 295(1.07)^x; 338

please help me!!

anonymous · Answer

note that $7\%=.07$ and to increase a number by $7\%$ you multiply by $1.07$

anonymous · Answer

to increase a number by $7\%$ $x$ times multiply by $(1.07)^x$

anonymous · Answer

:/ im still confused

anonymous · Answer

ok suppose you want to increase a number by 7%, like say you want a final price after a 7% sales tax
and lets say the thing you are buying cost $50
then the total price would be $50+.07\times 50=50+3.5=53.5$
another way to calculate this is by the distributive law 
$50+.07\times 50=50(1+.07)=50(1.07)$

anonymous · Answer

in other words, to increase a number by 7% you can either 
a) find 7% of that number and add it to the original number, or 
b) multiply that number by $1.07$

anonymous · Answer

now if you want to increase a number $P$  by 7% three times i a row, you can write in one step 
$$P(1.07)^3$$