Question

Can somebody please help with the steps to doing this ??


Part 1: Make up an angle measure for angle C and a length for one of the sides (AB, BC, or CA). Part 2: Use a trigonometric ratio (sine, cosine, or tangent) to solve for one of the other side lengths.

Answer 1

Part 1: c = 45 and length for CA is 5??

Answer 2

If m<C = 45, then m<A = 45, and m<B = 90.
You have a 45-45-90 triangle.
In a 45-45-90 traingle, the two legs are congruent (they have the same length).
The hypotenuse is sqrt(2) times longer than the 2 legs.

Answer 3

Since C is 45, then so is A. So, this will be an isosceles triangle and the measure of AB will equal the measure of BC.

The sine of C = AB/AC. sine 45 = AB/AC

(AC) sine 45 = AB = BC

Answer 4

btw the sine 45 = [sqrt(2)] / 2

Answer 5

Its supposed to be a right triangle.. i just added the angle measures on my own

Answer 6

Yes. All the above that I wrote bore that in mind.

Answer 7

So, AB = (5)(sqrt 2) / 2

Answer 8

thats the answer?

Answer 9

For the length of AB, that's the answer. If you multiplied it out, you would get

AB = 3.53553 etc.

Answer 10

Is this making sense to you now?

Answer 11

yes alot more than before !

Answer 12

It's good that this is going well for you. Remember, sine = opposite over hypotenuse.

Answer 13

Good luck to you in all of your studies and thx for the recognition! @AshhSmith

Answer 14

ty !

Answer 15

uw!