Question

What is the length of the major and minor axis?

Answer 1

this you visualize

Answer 2

i also need the equation of the ellipse if possible

Answer 3

from -1 to -9 is 8 units for the length of the major axis

Answer 4

center is at \((2,-5)\) so the equation will look like
\[\frac{(y+5)^2}{a^2}+\frac{(x-2)^2}{b^2}=1\] the \(y\) comes first because of the orientation

Answer 5

thank you so so much, really helpful, so the length of the major axis is 8 then?

Answer 6

half of 8 is 4, vertices are four units up and down from the center, so you know \(a=4\) and therefore it will be
\[\frac{(y+5)^2}{16}+\frac{(x-2)^2}{b^2}=1\]

Answer 7

so that equation would be the length of the major axis? can i simplify that more? @satellite73

Answer 8

you need \(b\)

Answer 9

how could i find that

Answer 10

the length of the minor axis is 6, again from your eyeballs. so \(b=3\) and \(b^2=9\) for your denominator

Answer 11

take a look at the purple math link, it will really help
gotta run

Answer 12

thanks so so much again!