Find the measures of an exterior angle and an interior angles given the number of sides of each regular polygon. Round to the nearest tenth, if necessary. Number of sides: 16
So I started out by doing (n-2)(180) And I substituted n for 16 because n is the number of sides. so.. (16-2)(180) 14(180) =2520
And then I tried to find out what the measure of the interior angles was.
Int angle=(n-2)* 180/n
ext angle=360/n
Now just divide by the number of sides
Yes that!! @ksaimouli I thought about that!!
R u sure? @zaynahf for some reason I thought it was wrong to do that.
then u forgot to divide /n or number of sides in this case 16 i think
Lemme seee
2520/16=157.5 So are you saying that 157.5 is the measure of an interior angle?
*SOrry, not the # of sides
16-2= 14 2520/14
And then.. 360/16 =22.5 for exterior angle?
Oh! 14 for the triangles?
@zaynahf
That makes each side become 180 for interior!?! whaaa...makes no sense..
I know, lol i just messed up
oh..so then how do I do this?
Sorry, its been a long time -_- Here, i found this: Exterior angles always add up to 360 no matter how many sides. So to find an interior angle, it's easiest to find the exterior angle and subtract it from 180 since interior + exterior = 180 So 1 16-gon: 360 / 16 = 22.5; 180 - 22.5 = 157.5 degrees
You were right :)
yes!!!
Ok good :P Sorry again.. i forgot that stuff
Lol its ok!
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