Use a matrix to find the solution to the system of equations. -8x-8y=-16 6x-9y=-108
what it the matrix you start with? Do you know that?
no thats just the whole question
You build ur first matrix from the coefficents
-8 -8 | -16 6 -9 | -108
A few Matrix rules 1) You can rearrange rows 2) You can multiply a row my a scaler 3) You can add rows 4) You CANNOT multiply rows
The goal is to get all 1's in the primary diagonal and zeros in the other spots. The first column is the x variable and the 2nd is the y variable.
the first row and third column number is what x equals and y equals the second row of the last column
the answer is one of thiese so how do i find that? (–6, 8) (6, 8) (8, –6) (6, –8)
You need to do a series of row operations
http://www.sparknotes.com/math/algebra2/systemsofthreeequations/section2.rhtml
this is a 3 equation system but it is the same principle for 2
can u break this down for me all the way to the answer when i read stuff i never can comprehend it but when i see the problem broke down i can understand it more.
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