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Mathematics 21 Online
OpenStudy (anonymous):

Use a matrix to find the solution to the system of equations. -8x-8y=-16 6x-9y=-108

OpenStudy (anonymous):

what it the matrix you start with? Do you know that?

OpenStudy (anonymous):

no thats just the whole question

OpenStudy (anonymous):

You build ur first matrix from the coefficents

OpenStudy (anonymous):

-8 -8 | -16 6 -9 | -108

OpenStudy (anonymous):

A few Matrix rules 1) You can rearrange rows 2) You can multiply a row my a scaler 3) You can add rows 4) You CANNOT multiply rows

OpenStudy (anonymous):

The goal is to get all 1's in the primary diagonal and zeros in the other spots. The first column is the x variable and the 2nd is the y variable.

OpenStudy (anonymous):

the first row and third column number is what x equals and y equals the second row of the last column

OpenStudy (anonymous):

the answer is one of thiese so how do i find that? (–6, 8) (6, 8) (8, –6) (6, –8)

OpenStudy (anonymous):

You need to do a series of row operations

OpenStudy (anonymous):

this is a 3 equation system but it is the same principle for 2

OpenStudy (anonymous):

can u break this down for me all the way to the answer when i read stuff i never can comprehend it but when i see the problem broke down i can understand it more.

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