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Mathematics 8 Online
OpenStudy (anonymous):

I dont understand how to do this equation

OpenStudy (anonymous):

\[\frac{ \sqrt{11} }{ 5\sqrt{132} }\]

OpenStudy (anonymous):

im stuck i have \[\frac{ \sqrt{11} }{ 10\sqrt{33} }\]

OpenStudy (whpalmer4):

33 = 11*3, right?

OpenStudy (anonymous):

yes

OpenStudy (whpalmer4):

So the denominator could be simplified some more

OpenStudy (whpalmer4):

\[10\sqrt{3*11} = 10\sqrt{3}\sqrt{11}\] and then you can cancel the \[\sqrt{11}\] top and bottom.

OpenStudy (anonymous):

so if the top and bottom square roots are the same i can cancel them right? it like \[\frac{ 3 }{ 3 }\] =1

OpenStudy (whpalmer4):

Yes, exactly. So what is the final result?

OpenStudy (anonymous):

the answer is \[10\sqrt{3}\]

OpenStudy (whpalmer4):

Close, but no cigar.

OpenStudy (whpalmer4):

That's the final denominator

OpenStudy (anonymous):

but isn't the numerator canceled?

OpenStudy (whpalmer4):

When you cancel the term from top and bottom, you are dividing both top and bottom by the term you cancel. The numerator (top) was \[\sqrt{11}\] but you are dividing it by that same value. You have \[\frac{\sqrt{11}/\sqrt{11}}{10\sqrt{3}\sqrt{11}/\sqrt{11}} = \frac{1}{10\sqrt{3}}\]

OpenStudy (whpalmer4):

Think of \[\frac{2}{8}\] which you could write as \[\frac{2}{2*2*2}\] just because the 2 in the numerator cancels out a 2 in the denominator doesn't make the answer 4, does it?

OpenStudy (anonymous):

okay I just checked the answer for this question in the book and it says \[\frac{ \sqrt{3} }{ 30 }\]

OpenStudy (whpalmer4):

Okay, what happens if you multiply my answer by \[\frac{\sqrt{3}}{\sqrt{3}}\]?

OpenStudy (anonymous):

oh wow its\[\frac{ \sqrt{3} }{ 30 }\]

OpenStudy (anonymous):

Thnx for the help very much

OpenStudy (whpalmer4):

You're welcome!

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