I dont understand how to do this equation
\[\frac{ \sqrt{11} }{ 5\sqrt{132} }\]
im stuck i have \[\frac{ \sqrt{11} }{ 10\sqrt{33} }\]
33 = 11*3, right?
yes
So the denominator could be simplified some more
\[10\sqrt{3*11} = 10\sqrt{3}\sqrt{11}\] and then you can cancel the \[\sqrt{11}\] top and bottom.
so if the top and bottom square roots are the same i can cancel them right? it like \[\frac{ 3 }{ 3 }\] =1
Yes, exactly. So what is the final result?
the answer is \[10\sqrt{3}\]
Close, but no cigar.
That's the final denominator
but isn't the numerator canceled?
When you cancel the term from top and bottom, you are dividing both top and bottom by the term you cancel. The numerator (top) was \[\sqrt{11}\] but you are dividing it by that same value. You have \[\frac{\sqrt{11}/\sqrt{11}}{10\sqrt{3}\sqrt{11}/\sqrt{11}} = \frac{1}{10\sqrt{3}}\]
Think of \[\frac{2}{8}\] which you could write as \[\frac{2}{2*2*2}\] just because the 2 in the numerator cancels out a 2 in the denominator doesn't make the answer 4, does it?
okay I just checked the answer for this question in the book and it says \[\frac{ \sqrt{3} }{ 30 }\]
Okay, what happens if you multiply my answer by \[\frac{\sqrt{3}}{\sqrt{3}}\]?
oh wow its\[\frac{ \sqrt{3} }{ 30 }\]
Thnx for the help very much
You're welcome!
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