Question

Find the coordinates of the vertex for the parabola whose equation is f(x) = (x + 3)^2 + 3
(-3,3)

(-3,-3)

(0,3)

(3,0)

Answer 1

The vertex for this particular parabola is its low-point: Where x + 3 is a minimum or at x = -3

So, (-3, 3)

Answer 2

This is in vertex form:
\[ a ( x - h )^{2}+ k\]
Where (h,k) is the vertex

Answer 3

Example:
\[a ( x - h) ^{2}+k\]
\[3 ( x+ 5)^{2}+2\]
The vertex would be -5, 2

Answer 4

\[f(x) = (x + 3)^2 + 3 \]
The easy thing that you should notice is that f(x)=y.
All you have to do is replace f(x) with y and then you move the "+3" to the Left Hand Side(LHS).
\[(x+3)^2= (y-3)\]
You should know the vertex straight away because of this:
\[(x-h)^2=(y-k)\]
Where the point (h, k) is the vertex.
Once you know that, you will know that (-3, 3) is the vertex in this question.